If α,β are roots of the equation ax²+bx+c=0 then the quadratic equation whose roots are 1/(aα+b)², 1/(aβ+b)², is
a. (a²)x²+(2ac−b²)x+1=0
b. (c²)x²+(2ac−b²)x+1=0
c. (a²c²)x²+(2ac−b²)x+1=0
c. (a²c²)x²+(2ac+b²)x+1=0