Given that the integers are consecutive, then: suppose: first number=x second number=x+1 third number=x+2 the product of the first two is: x(x+1) Given that the product is 5 less than 5(x+2) then x(x+1)+5=5(x+2) x^2+x+5=5x+10 simplifying the above we get: x^2-4x-5=0 x=5 or x=-1 since the numbers are positive then the smallest number is 5
