Respuesta :

mendietajose513
 [tex](a^6b^{12})^{1/3} [/tex] ========> [tex]a^2b^4[/tex]
[tex] \frac{(a^5b^3)^{1/2} }{(ab)^{- \frac{1}{2} } } [/tex]  ======> [tex]a^3b^2[/tex]
[tex] (\frac{a^{5} }{ a^{-3} b^{-4} } )^{ \frac{1}{4}} [/tex] ========> [tex]a^2b[/tex]
[tex]( \frac{a^3}{ab^{-6} } )^{ \frac{1}{2} }[/tex] ========> [tex]ab^3[/tex]

aencabo
The answers are the following:
(a^6b^12)^1/3 = a^2b^4
(a^5b^3)^1/2 / (ab)^-1/2 = a^3b^2
(a^5/a^-3b^-4)^1/4=a^2b
(a^3/ab^-6)^1/2 = ab^3

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