hey7963 hey7963
  • 16-07-2018
  • Mathematics
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What is the vertex of this parabola y=-4x^2+8x-12

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Narax
Narax Narax
  • 16-07-2018

The answer you are looking for is (1, -8)

remember that: x=[(-b/2a)]

and that the problem is set up as y=ax^2+bx+c

calculate:

x=[-8/2(-4)]

x=[-8/-8]

x=1

then:

y=(-4)*1^2+(8*1)-12

y=(-4)+8-12

y=(-4)+8-12

y=4-12

y=(-8)

(1, -8)


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