The question is not formatted correctly. The proper question should be
What would happen to the rate of a reaction with rate law
rate=k [NO]2[H2]
if the concentration of H2 were halved?
Answer:
Rate would be halved.
Explanation:-
Let originally [NO]= 1 and [H2]=1.
Then original rate= k [1]2 [1] = k.
Now if [H2] is halved then new [H2] = 1/2
While [NO] remains same.
Then
new rate = k [1]2 [1/2] = k/2
Thus the rate is halved.
Answer:
the rate would also be halved
Explanation:
i just did the test :D
