The percentage of chloride in the sample is 10.11% (answer B)
calculation and explanation
step 1: find the moles of AgNo3
moles = molarity x volume in liters
volume in liters= 70.90/100=0.709 L
moles=0.2010 x0.709=0.01425 moles which is also moles of cl-
step 2:find the actual mass of Cl-
mass = moles x molar mass
= 0.01425 moles x 35.5 g/mol= 0.5059 grams
step 3: find the % mass
actual mass/theoretical mass x 100
0.5059 g/5.000 g x100 =10.11%
