Problem 1
[tex]\dfrac{16}{(4- -3-1-8)}[/tex]
[tex]\dfrac{16}{(4+3-1-8)}[/tex]
[tex]\dfrac{16}{(7-9)} = \dfrac{16}{-2}[/tex]
-8 Answer
Problem 2
(8 - 3)^2 - (3 + 10)
5^2 - (13)
25 - 13
12 Answer
