brendaad32
brendaad32 brendaad32
  • 20-09-2018
  • Mathematics
contestada

Precalculus question. Please help me and thank you .

Precalculus question Please help me and thank you class=

Respuesta :

lisboa lisboa
  • 20-09-2018

We know,

sin(x) and cos(x) have minimum value equal to -1 and maximum value is 1.

Maximum value of sin(x) is 1

So we replace sin by 1 in our given equation

[tex]y=-2+5sin(\frac{\pi }{12}(x-2))[/tex]

When we replace sin by 1 we will get

[tex]y=-2+5(1))[/tex]

y= -2+5 = 3

So maximum value is 3


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