kadi55
contestada

There are 21 animals on Farmer Cole’s farm — all sheep and chickens. If the animals have a total of 56 legs, how many of each type of animal lives on his farm? Write a system of equations, and use the equal values method to solve it.

Respuesta :

apologiabiology

sheep usually have 4 legs each

chickens usually have 2 legs each


if c=number of shep and s=number of chickents, then c+s=21

total legs is 56, so 2c+4s=56


system of equations is c+s=21 and 2c+4s=56

equal values method? why do they have to keep changing names, it doesn't sound like subsitution so I'm assuming they mean linear combinations


c+s=21

2c+4s=56

multiply first equation by -2 and add to 2nd equation


-2c-2s=-42

2c+4s=56 +

0c+2s=14


2s=14

divide by 2

s=7


sub back

c+s=21

c+7=21

c=14


14 chickens and 7 sheep

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