Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).

y + 1 = -2(x – 5)

y – 1 = -2(x – 5)

y – 5 = -2(x + 1)

y -5 = -2(x – 1)

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point given and a slope from the equation. We will chose point-slope since we have a point and the slope.

We will substitute [tex]m=-2[/tex] and [tex]x_1=5\\y_1=-1[/tex].

[tex]y-(-1)=-2 (x-5)[/tex]

[tex]y+1=-2(x-5)[/tex]

This is the equation of the line with slope -2 that passes through (5,-1).

Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1). y + 1 = -2(x – 5) y – 1 = -2(x – 5) y – 5 = -2(x + 1) y -5 = -2(x – 1)

Respuesta :

Otras preguntas

Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).

y + 1 = -2(x – 5)

y – 1 = -2(x – 5)

y – 5 = -2(x + 1)

y -5 = -2(x – 1)