4ssmuncher69 4ssmuncher69

18-01-2019
Chemistry

contestada

What volume of 2M HCl, a common laboratory stock solution, must be used to prepare 150.0 mL of 1M HCl? show work please

Respuesta :

superman1987 superman1987

27-01-2019

Answer: 75.0 mL.

Explanation:

We have a rule says that "the number of millimoles before dilution is the same after dilution".

This rule can be expressed as (M1V1)before dilution = (M2V2)after dilution.

Before dilution: M1 = 2.0 M & V1 = ??? (The volume needed to be calculated)

After dilution: M2 = 1.0 M & V2 = 150.0 mL.

Now, the volume must be used from the stock to prepare the desired solution:

V1 before dilution = (M2V2)after dilution / (M1) = (1.0 M x 150.0 mL) / (2.0 M) = 75.0 mL.

Answer Link

Otras preguntas

Use the drop–down menus to select the best answers. There is/are bone(s) in the lower arm. There is/are bone(s) in the upper arm.

Some school students are raising money for a charity. Their goal is to raise $1000. They already have $232 from bake sales. To raise the remainder, they are pla

which condition would disturb the hardy-weinberg equilibrium and cause the gene pool to change?

how to find the volume of an oven with the inside dimensions 3 ft by 1.5 ft by 3 ft

Your classmate says that the farther the two atoms are apart in a bond, the larger the dipole moment will be. Is your classmate correct

What additions were made by Andrew Jackson to the White House?

10000% + 10% X 50% = ?

Did Tom Robinson ever have a chance at a fair trial?

Write the percent as a decimal. 178%

What do you think of this hairstyle?