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  • 19-01-2019
  • Mathematics
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Given: ABCD is a ∥-gram; DE ∩ AB =F
Prove: △ADF∼△CDE

Given ABCD is a gram DE AB F Prove ADFCDE class=

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flightbath flightbath
  • 28-01-2019

Answer:

By AA similarity

Step-by-step explanation:

We have been given that ABCD is a parallelogram

So, by the property of parallelogram AB ||CD and FD is cutting the line BC

Hence, FD is transverse line. In transverse line alternate angles are equal.

Therefore, ∠AFD=∠EDC  (alternate interior angles)

And ∠FAD=∠ECD (opposite angles in parallelogram)

Therefore, by AA similarity △ADF∼△CDE

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