emanuelhf99 emanuelhf99
  • 17-02-2019
  • Mathematics
contestada

Evaluate for x = 2 and y = 3: x^2 y^-3 /x^-1 y

Respuesta :

gmany
gmany gmany
  • 17-02-2019

Answer:

[tex]\large\boxed{\dfrac{8}{81}}[/tex]

Step-by-step explanation:

First simplify the expression using:

[tex]\dfrac{a^n}{a^m}=a^{n-m}[/tex]

[tex]\dfrac{x^2y^{-3}}{x^{-1}y}=x^{2-(-1)}y^{-3-1}=x^3y^{-4}[/tex]

Use

[tex]a^{-n}=\dfrac{1}{a^n}[/tex]

[tex]x^3y^{-4}=\dfrac{x^3}{y^4}[/tex]

Put the values of x = 2 and y = 3 to the expression:

[tex]\dfrac{2^3}{3^4}=\dfrac{8}{81}[/tex]

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