Correct answer:
[tex]\boxed{v_{out}=2,85V}[/tex]
Explanation:
We can use voltage divider to solve this problem that is defined as the passive linear circuit producing an output voltage [tex]v_{out}[/tex] that is a fraction of its input voltage [tex]v_{in}[/tex]. So we can use the formula:
[tex]v_{out}=\frac{R_{2}}{R_{1}+R_{2}}v_{in}, \ where \ v_{in}=v_{s}=4V \\ \\ \therefore v_{out}=\frac{35}{14+35}(4) \\ \\ \therefore v_{out}=2,85V[/tex]
