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  • 21-04-2016
  • Mathematics
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factor 2x^3 -6x^2 -80x completely

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  • 21-04-2016
[tex]2x^3 -6x^2 -80x \\ \\ 2x( \frac{2x^3}{2x} + \frac{-6x^2}{2x} + \frac{-80x}{2x} ) \\ \\ 2x(x^2 - 3x - 40) \\ \\ 2x(x - 8)(x + 5) \\ \\ [/tex]

The answer is: 2x(x - 8)(x + 5).
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