jsaenzrufasto70 jsaenzrufasto70
  • 17-04-2019
  • Mathematics
contestada

en un triangulo rectangulo ABC (B=90) REDUCE:

J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa

Respuesta :

janthony36
janthony36 janthony36
  • 17-04-2019

Answer:

puc provar, però no sé lemme see

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