efrenlujan23 efrenlujan23
  • 20-05-2019
  • Mathematics
contestada

Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°.

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 21-05-2019

ANSWER

36√3 square units.

EXPLANATION

The area of a parallelogram is obtained by multiplying the base by the height.

We use the sine ratio to obtain the height.

[tex] \sin(60 \degree) = \frac{h}{6} [/tex]

[tex]h = 6 \sin(60 \degree) [/tex]

[tex]h = 3 \sqrt{3} [/tex]

The area becomes:

[tex]12 \times 3 \sqrt{3} = 36 \sqrt{3} {units}^{2} [/tex]

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