Answer:
Output of plant=207.18 MW
Explanation:
Given input energy Q=450 MW
Brayton cycle efficiency[tex]\eta_1=24[/tex]%
Rankine cycle efficiency [tex]\eta_2=29[/tex]%
Combined efficiency for two cycle given as follow
[tex]\eta _b=\eta _1+\eta _2-\eta _1\eta _2[/tex]
[tex]\eta _b=0.24+0.29-0.24\times 0.29[/tex]
[tex]\eta_b=0.4604[/tex]
We know that efficiency [tex]\eta =\dfrac{out\ put}{in\ put}[/tex]
out put of plant=[tex]450\times 0.4604[/tex]
So output of plant=207.18 MW
