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A 16.0g bullet is shot into a wood block at rest with a mass of 2450 g on a frictionless surface. The block moves 1.2m/s after the bullet strikes and becomes lodged in the block. Find the speed of the bullet before striking the block.

Respuesta :

Answer:

The speed of the bullet before striking the block is 185 m/s.

Explanation:

Given that,

Mass of bullet = 16.0 g

Mass of wood block = 2450 g

Velocity of block = 1.2 m/s

We need to calculate the speed of the bullet before striking the block

Using equation of conservation of momentum

[tex]P_{i}=P_{f}[/tex]

[tex]m_{b}v_{b}=(m_{b}+m_{w})v[/tex]

[tex]16.0v=(0.016+2.450)\times1.2[/tex]

[tex]v=\dfrac{0.016+2.450}{0.0160}\times1.2[/tex]

[tex]v=185\ m/s[/tex]

Hence, The speed of the bullet before striking the block is 185 m/s.

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