parksdeyshanique
parksdeyshanique parksdeyshanique
  • 16-09-2019
  • Mathematics
contestada

PLEASE HELP! I REALLY AM CONFUSED

PLEASE HELP I REALLY AM CONFUSED class=

Respuesta :

LammettHash
LammettHash LammettHash
  • 16-09-2019

[tex]\log_7(x^2+4x-11)=\dfrac52[/tex]

[tex]7^{\log_7(x^2+4x-11)}=7^{\frac52}[/tex]

[tex]x^2+4x-11=7^{\frac52}[/tex]

[tex]x^2+4x-\left(11+7^{\frac52}\right)=0[/tex]

Now you can use the quadratic formula to solve for [tex]x[/tex].

[tex]x=-2\pm\sqrt{15+7^{\frac52}}[/tex]

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