kaylard9485 kaylard9485
  • 17-10-2019
  • Mathematics
contestada

_____ 10. How many milligrams of active ingredient are required to prepare 10 mL of 0.3% (w/v) solution?

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valenbraca
valenbraca valenbraca
  • 19-10-2019

Answer:

30 mg of active ingredient is required to prepare a 0.3% (W/V) solution.

Step-by-step explanation:

0.3% (w/v) solution can also be expressed as: 0.3 g active ingredient for 100 ml of solution.

So:

[tex]\frac{0.3g}{100 ml} *\frac{1000mg}{1g}*10ml[/tex]= 30 mg

In conclusion, we need to weigh 30 mg of active ingredient and then dilute it in 10 ml of water.

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