najwadaaboul2004 najwadaaboul2004

20-10-2019
Mathematics

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k^3-27 in difference of cubes

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mathtutors1927 mathtutors1927

20-10-2019

Answer:

(k - 3)(k^2 + 3k + 9)

Step-by-step explanation:

Base equation:

(k^3 - 3^3)

The first bracket will be a - b, second will be:

a^2 + ab + b^2

(k - 3)(k^2 + 3k + 9)

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