Answer:
42°
Step-by-step explanation:
Since it is an isosceles triangle, the base angles are equal. Let the base angles be [tex]x[/tex].
Hence, $x+x+48=180$, since sum of internal angles in ∆ABC is 180°.
Hence, $x=132/2=66°$
In ∆PBC,
[tex] PB=PC\\
\implies m\angle PBC= m\angle PCB[/tex]
But, [tex] \angle ABD= \angle PBC =\frac{1}{2} m\angle ABC =24°\\
\implies m\angle PCB=24°\\
Now,\\
m \angle ACB= m\angle PCD + m\angle PCB\\
\implies m\angle PCD= 66-24=42°[/tex]
