Randolphsafaa Randolphsafaa
  • 18-11-2019
  • Mathematics
contestada

9.10 raised to seven is how many times as large as 3. 10 raised to negative 2

Respuesta :

VioletBrennan VioletBrennan
  • 30-11-2019

Answer:

49,660,733.96

Step-by-step explanation:

Required to Find

How many times is [tex]9.1^{7}[/tex] greater than [tex]3.1^{-2}[/tex]

⇒

To find the required factor ,we have to divide the numbers

⇒The required number

[tex]=\frac{9.1^{7} }{3.1^{-2} } =9.1^{7} \times3.1^{2} =5167610.19 \times 9.21=49660733.96[/tex]

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