Answer:
35.36776 Hz
Explanation:
B = Magnetic field = [tex]9\times 10^{-3}}\ T[/tex]
[tex]E_m[/tex] = Maximum voltage = 20 V
d = Diameter of coil = 40 cm = 0.4 m
A = Area = [tex]\pi \frac{d}{2}^2=\pi 0.2^2[/tex]
N = Number of turns = 500
[tex]\omega[/tex] = Angular velocity
Maximum emf is given by
[tex]E_m=NAB\omega\\\Rightarrow \omega=\frac{E_m}{NAB}\\\Rightarrow \omega=\frac{20}{500\times \pi\times 0.2^2\times 9\times 10^{-3}}\\\Rightarrow \omega=35.36776\ Hz[/tex]
The angular velocity would be 35.36776 Hz
