Answer:
change in volume of ballon is 2.109 L
Explanation:
Given data:
initial temperature = 199 degree C = 292 K
pressure P1 = 1.09 atm
initial volume = 1.00 L
pressure P2 = 222 torr = 0.292 atm
temperature T2 = - 28 oC = 245 K
we know that[tex]\frac{P1 V1}{T1} = \frac{P2 V2}{T2}[/tex]
[tex]\frac{1.09 \times 1}{292} = \frac{0.292 \times V2}{245}[/tex]
V2 = 3.109 L
change in volume of ballon = 3.109 - 1 = 2.109 L
