The fence around a rectangular piece of property is 156 meters long. If the area of the property is 1485 square meters, what are the dimensions of the property? (HINT: set up the equations and
solve for y to graph.)

The perimeter is twice the sum of adjacent side lengths, so the sum of the dimensions is 78 meters. If x is one of the dimensions, then 78-x is the other, and the area is their product:

x(78 -x) = 1485

Subtracting the left side, we get ...

x^2 -78x +1485 = 0

This can be graphed as ...

y = x^2 -78x +1485

and the zeros will reveal the dimensions.

The attached graph shows them to be ...

33 by 45 meters

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The fence around a rectangular piece of property is 156 meters long. If the area of the property is 1485 square meters, what are the dimensions of the property? (HINT: set up the equations andsolve for y to graph.)​

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The fence around a rectangular piece of property is 156 meters long. If the area of the property is 1485 square meters, what are the dimensions of the property? (HINT: set up the equations and
solve for y to graph.)