booplesnoop163 booplesnoop163
  • 18-12-2019
  • Mathematics
contestada

What is the average rate of change of the function f(x)=120(.1)^x from x=0 to x=2

Respuesta :

rani01654 rani01654
  • 30-12-2019

Answer:

- 59.4

Step-by-step explanation:

The given function is [tex]f(x) = 120(0.1)^{x}[/tex]

Therefore, at x = 0, [tex]f(0) = 120(0.1)^{0} = 120[/tex] and  

at x = 2, [tex]f(2) = 120(0.1)^{2} = 1.2[/tex]

Hence, the average rate of change of the given function from x = 0 to x = 2 will be  

[tex]\frac{f(2) - f(0)}{2 - 0}[/tex]

= [tex]\frac{1.2 - 120}{2 - 0}[/tex]

= - 59.4 (Answer)

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