Respuesta :
Answer:
A) [tex]H_{0}[/tex]: p=0.5 (At least half of the workers are women,fair)
B) [tex]H_{a}[/tex]: p<0.5 (Less than half of the workers are women,unfair)
C) critical value of the test statistic is 1.64 (one tailed)
D) Test statistic is ≈ 0.29
E) Since 0.29<1.64, we fail to reject the null hypothesis. There is no significant evidence that the company has unfair hiring practices at 0.05 significance level.
Step-by-step explanation:
Let p be the proportion of women workers in the company. Null and alternative hypotheses are
[tex]H_{0}[/tex]: p=0.5 (At least half of the workers are women,fair)
[tex]H_{a}[/tex]: p<0.5 (Less than half of the workers are women,unfair)
Test statistic can be found using the equation:
z=[tex]\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }[/tex] where
- p(s) is the sample proportion of women workers ([tex]\frac{55}{107} =0.514[/tex])
- p is the proportion assumed under null hypothesis. (0.5)
- N is the sample size (55+52=107)
Then z=[tex]\frac{0.514-0.5}{\sqrt{\frac{0.5*0.5}{107} } }[/tex] ≈ 0.29
For alpha 0.05, critical value of the test statistic is 1.64 (one tailed)
Since 0.29<1.64, we fail to reject the null hypothesis. There is no significant evidence that the company has unfair hiring practices at 0.05 significance level.