Answer:
0.78
Step-by-step explanation:
given that 80% of an airline's flights depart on-time and 20% do not.
Of those that depart on-time, 95% arrive on-time. Of those that depart late, 10% arrive on-time
Let A be the event that flight departs on time.
Now A and A' are mutually exclusive and exhaustive
Let B be the event the flight arrives on time
Using total probability calculation we have
the chance of someone taking a flight that will arrive on-time
= P(B)
=[tex]P(A)+P(A'B)\\= 0.80(0.95) +0.20(0.10)\\= 0.76+0.02\\=0.78[/tex]
