cesslyfought77
cesslyfought77 cesslyfought77
  • 17-02-2020
  • Mathematics
contestada

Solve the given equation.


[tex]\sqrt{6x-1}+1=5[/tex]

Respuesta :

jimrgrant1 jimrgrant1
  • 17-02-2020

Answer:

x = [tex]\frac{17}{6}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{6x-1}[/tex] + 1 = 5 ( subtract 1 from both sides )

[tex]\sqrt{6x-1}[/tex] = 4 ( to clear the radical, square both sides )

6x - 1 = 4²

6x - 1 = 16 ( add 1 to both sides )

6x = 17 ( divide both sides by 6 )

x = [tex]\frac{17}{6}[/tex]

Answer Link
safojabbour safojabbour
  • 17-02-2020
radical 6x-1 = 5-1
radical 6x-1=4
square both sides to get rid of radical
6x-1=16
6x= 16+1
6x=17
divide by 6, x=17/6
Answer Link

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