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A ball is thrown from ground level straight up into the air at an intitial velocity of 54 feet per second. The height of the ball t seconds after it is thrown is given by the formula h(t)=54t-16’2. How many seconds after the ball is thrown will it return to the ground

Respuesta :

Answer:

3 3/8 seconds.

Step-by-step explanation:

When it reaches the ground h = 0 so:

54t - 16t^2 = 0

16t^2 - 54t = 0

2t(8t - 27) = 0

t = 0 or t =  27/8   (we ignore the t = 0 ) so:

t =   3 3/8 seconds.

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