Answer:
[tex]\frac{x-4}{15x^2y^3}[/tex]
Step-by-step explanation:
Given
[tex]\frac{x-4}{30x^2y^3}[/tex] + [tex]\frac{x-4}{30x^2y^3}[/tex]
Since the denominators are common, add the numerators leaving the denominator.
= [tex]\frac{x-4+x-4}{30x^2y^3}[/tex]
= [tex]\frac{2(x-4)}{30x^2y^3}[/tex]
Cancel the 2 and 30 by 2 on the numerator/ denominator, leaving
= [tex]\frac{x-4}{15x^2y^3}[/tex]
