drayonahchandler23 drayonahchandler23
  • 16-03-2020
  • Physics
contestada

what is the force on a 1000 kilogram -elevator that is falling freely under the accerleration of gravity only (9.8m/s2)?

Respuesta :

blarvind blarvind
  • 17-03-2020

Answer:

[tex]W = 9800 \ \rm N.[/tex]

Explanation:

Given data:

Mass, [tex]m = 1000 \ kg[/tex]

Acceleration due to gravity, [tex]g = 9.8 \ m/s^{2}[/tex]

Here, the elevator is in free-fall. The force experienced by the elevator would be equal to its weight.

Thus,

[tex]W = mg[/tex]

[tex]W = 1000 \ kg \times 9.80 \ m/s^{2}[/tex]

[tex]W = 9800 \ \rm N.[/tex]

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