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imagine that you could transport a simple pendulum from earth to another planet or moon, where the free-fall acceleration is one-fifth that on Earth. By what factor would the pendulum's frequency be changed

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Answer:

Explanation:

Acceleration due to gravity on the other planet = g/5

where, g is the acceleration due to gravity on the earth.

The frequency of the simple pendulum on earth is given by

[tex]f \alpha \sqrt{g}[/tex]    .... (1)

the frequency on the other planet is given by

[tex]f' \alpha \sqrt{g'}[/tex]  .... (2)

Divide equation (2) by (1)

[tex]\frac{f'}{f} \alpha \sqrt{\frac{g'}{g}}[/tex]

[tex]\frac{f'}{f} \alpha \sqrt{\frac{g}{5g}}[/tex]

f' = 0.44 f

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