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Determine the magnitude of the magnetic flux through the south-facing window of a house in British Columbia, where Earth's \overrightarrow{B} field has a magnitude of 5.8 × 10?5 T and the direction of \overrightarrow{B} field is 72? below horizontal with the horizontal component of\overrightarrow{B}field directed to the north. Assume the area of the window is 4.5 m^{2}

Question

Determine the magnitude of the magnetic flux through the west-facing window that has the same area.

Respuesta :

boffeemadrid

Answer:

0

Explanation:

B = Magnetic field = [tex]5.8\times 10^{-5}\ T[/tex]

A = Area of window = [tex]4.5\ m^2[/tex]

[tex]\theta[/tex] =Angle of the magnetic field = [tex]90^{\circ}[/tex]

Magnetic flux is given by

[tex]\phi=BA\cos \theta\\\Rightarrow \phi=5.8\times 10^{-5}\times 4.5\times \cos 90^{\circ}\\\Rightarrow \phi=0\ Tm^2[/tex]

The magnitude of the magnetic flux through the west-facing window that has the same area is 0