Y= 1/3x+3
Y=2x-2
How can I solve of systems of equation substitution.?

Question

19-03-2020
Mathematics

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Y= 1/3x+3
Y=2x-2
How can I solve of systems of equation substitution.?

Respuesta :

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TenzinTsesang TenzinTsesang · Answer 1 · 2020-03-19T03:03:36+01:00

TenzinTsesang TenzinTsesang

19-03-2020

Answer:

x=3

Step-by-step explanation:

Since both equations solve for y, set the equations equal to each other:

1/3x+3 = 2x-2

Then solve for x:

1/3x-2x=-2-3

1/3x-6/3x=-5

-5/3x=-5

-5x=-5*3

-5x=-15

x=-15/-5

x=3

Answer Link

panosm0809 panosm0809 · Answer 2 · 2020-03-19T03:10:06+01:00

panosm0809 panosm0809

19-03-2020

Answer:

x=3

Step-by-step explanation:

1/3x+3 = 2x-2

Then solve for x:

1/3x-2x=-2-3

1/3x-6/3x=-5

-5/3x=-5

-5x=-5*3

-5x=-15

x=-15/-5

x=3

Answer Link

Y= 1/3x+3 Y=2x-2 How can I solve of systems of equation substitution.?

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Otras preguntas

Y= 1/3x+3
Y=2x-2
How can I solve of systems of equation substitution.?