brazzyjaay01 brazzyjaay01
  • 19-04-2020
  • Mathematics
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Can someone please help me on number 19

Can someone please help me on number 19 class=

Respuesta :

ChemBen
ChemBen ChemBen
  • 19-04-2020

Answer:

[tex]12\pi x^{2} +21\pi x+9\pi[/tex]

Step-by-step explanation:

[tex]V=Bh=\pi r^{2} h = \pi (4x+3)^{2} (3x+3) = \pi (12x^{2}+12x+9x+9 )=12\pi x^{2} +21\pi x+9\pi[/tex]

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