wroberson56 wroberson56

18-08-2016
Mathematics

contestada

Change the w-3/w+5 fraction into an equivalent fraction with the denominator w2 + w – 20

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dalendrk dalendrk

18-08-2016

[tex]\dfrac{w-3}{w+5}=\dfrac{(w-3)(w-4)}{(w+5)(w-4)}=\dfrac{w^2-4w-3w+12}{w^2+5w-4w-20}=\dfrac{w^2-7w+12}{w^2+w-20}[/tex]

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