Answer: The volume occupied by 2.50 moles of [tex]N_2[/tex] gas at STP is 56.0L
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 2.50
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]273K[/tex] (at STP)
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{2.50mol\times 0.0821Latm/K mol\times 273K}{1atm}=56.0L[/tex]
Thus the volume occupied by 2.50 moles of [tex]N_2[/tex] gas at STP is 56.0L
