miajaynnezeringo
miajaynnezeringo miajaynnezeringo
  • 16-06-2020
  • Mathematics
contestada

Solve for x. 4x + 3 < 9

Respuesta :

Hi1315
Hi1315 Hi1315
  • 16-06-2020

Answer:

[tex]x < \frac{3}{2} \\ [/tex]

Step-by-step explanation:

[tex]4x + 3 < 9 \\ 4x < 9 - 3 \\ 4x < 6 \\ \frac{4x}{4} < \frac{6}{4} \\ x < \frac{3}{2} [/tex]

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