ambermarquez022 ambermarquez022
  • 17-06-2020
  • Mathematics
contestada

The value of y varies inversely as the cube of x and y=1 when x=6. Find the value of y when x =2.

The value of y varies inversely as the cube of x and y1 when x6 Find the value of y when x 2 class=

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adioabiola
adioabiola adioabiola
  • 22-06-2020

Answer:

y=27 when x=2

Step-by-step explanation:

y varies inversely as the cube of x

y=k(1/X^3)

y=1 when x=6

y=k(1/X^3)

1=k(1/6^3)

1=k(1/216)

k=1÷1/216

K=1×216/1

k=216

find y when x=2

y=k(1/X^3)

y=216(1/2^3)

y=216(1/8)

y=216/8

y=27

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