asmo1341 asmo1341

20-06-2020
Chemistry

contestada

the volume, in liters, of 538 g of CO2

Respuesta :

barakaodoyo5 barakaodoyo5

20-06-2020

Answer:

12.23moles in 1000cm3

Explanation:

Mass=moles×molermass

538=44xY

Y=538÷44

Y=12.23moles in 1000cm3

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