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there is a cell phone tower in the field across from sabers house. if saber walks 50 feet from the tower and finds the angle of elevation from his position to the top of the tower to be 60 degrees, how tall is the tower

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facundo3141592

Answer: 86.6ft

Step-by-step explanation:

Here we can construct a triangle rectangle.

First, the height of the tower is one of the cathetus, and is the value that we want to find X. The distance between Saber and the tower is the other cathetus, and we know that it is 50ft. And this cathetus is adjacent to the angle of 60°.

Then we can use the relationship:

Tan(angle) = (opposite cathetus)/(adjacent cathetus)

Then: Tan(60°) = X/50ft.

Tan(60°)*50ft = 86.6ft = X

Then the height of the tower is 86.6ft

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