Respuesta :

Answer:

Step-by-step explanation:

[tex]\frac{(1-cosA)^2+sin^2A}{sinA(1-cosA) }=\frac{1-2cosA+cos^2A+sin^2 A}{sinA(1-cos A)}[/tex]

[tex]=\frac{2-2cos A}{sinA(1-cosA)}[/tex]

[tex]=\frac{2(1-cosA)}{sinA(1-cosA)}=\frac{2}{sinA}=2cscA[/tex]