Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
2r + 3s = - 5 → (1)
6s = 2r → (2) ( divide both sides by 2 ), then
r = 3s
Substitute r = 3s into (1)
2(3s) + 3s = - 5
6s + 3s = - 5
9s = - 5 ( divide both sides by 9 )
s = - [tex]\frac{5}{9}[/tex]
Substitute this value into either of the 2 equations and evaluate for r
Substituting into r = 3s, then
r = 3 × - [tex]\frac{5}{9}[/tex] = - [tex]\frac{5}{3}[/tex]
Solution is r = - [tex]\frac{5}{3}[/tex] and s = - [tex]\frac{5}{9}[/tex]
