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A ball is pushed down a hill so that it starts with a velocity of 2.0 m/s. It accelerates at a rate of 0.50 m/s2 for the length of the hill, 10.0 m. What is the velocity of the ball at the bottom of the hill?

Respuesta :

MathPhys

Answer:

3.7 m/s

Explanation:

Given:

Δx = 10.0 m

v₀ = 2.0 m/s

a = 0.50 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (2.0 m/s)² + 2 (0.50 m/s²) (10.0 m)

v = 3.7 m/s

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