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Given the following probability distribution, what is the expected value of the random variable X? X P(X) 100 .10 150 .20 200 .30 250 .30 300 .10 Sum1.00 Multiple Choice 175 150 200 205

Respuesta :

Answer:

d) 205

Step-by-step explanation:

Step(i):-

x             :   100      150      200      250      300

p(X=x)    :   0.10     0.20    0.30     0.30      0.10

Step(ii):-

Let 'X' be the discrete random variable

Expected value of the random variable

   E(X) = ∑ x P(X=x)

           =  100 X 0.10 + 150 X 0.20 + 200 X 0.30 +250 X 0.30 + 300 X 0.10

          =   205

Final answer:-

The expected value     E(X) = 205

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