Answer:
17,300 m
Explanation:
Using kinematic equations, first find the time it takes to land.
Δy = v₀ t + ½ at²
0 m = (420 sin 53.0° m/s) t + ½ (-9.8 m/s²) t²
t = 0 s or 68.5 s
The horizontal distance it moves in that time is:
Δx = v₀ t + ½ at²
Δx = (420 cos 53.0° m/s) (68.5 s) + ½ (0 m/s²) (68.5 s)²
Δx = 17,300 m
Alternatively, you can use the range equation:
R = v₀² sin(2θ) / g
R = (420 m/s)² sin(2 × 53.0°) / (9.8 m/s²)
R = 17,300 m
