ecolongarcia10p8ckjp ecolongarcia10p8ckjp

17-09-2020
Chemistry

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Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left after 15 days?

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riapotharlanka riapotharlanka

17-09-2020

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

Let's round that up to 4

That means 15 days is around 4 half lives

4 half lives means 1/16 of the original mass will be left

25/16 = 0.390625

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